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class can be output as though they were predefined types Furthermore because input streams and output streams are of different types, statements such as

Q<I>o = 0,

cin << x;

fail at compile time Input and output have their respective problems For input, how do we detect errors For output, how can we finely control the format

(15.16)

In the preceding example, what happens if the user does not provide two integers but instead provides a sequence of letters In that case we have an input error and two things happen First, the result of the expression will be false, so we can run a test to determine if we do not get the input that we expect, as in

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An estimate of f3 can be obtained by minimizing the function g(b) = Ea(r)e i , where e i = Yi - b'Xi' ri is the rank of e i , and a(r) is the score Function (66) (or, in vector notation, (67 is the special case in which a(r) = r - i(n + 1) 66b The function g(b) is known to be well behaved with respect to minimization It is a convex function (see Hettmansperger, 1984, p 234), which implies that the condition Vg(bO) = 0 is sufficient to ensure that bO minimizes the function However, there does not necessarily exist a point bO satisfying Vg(bO) = 0, that is, at which all the partial derivatives exist and are o A necessary and sufficient criterion for bO to minimize g(b) is that at bO, for each j = 1, ...

cineof (

returns t r u e if the end-of-file caused a read to fail Be sure to remember that eof is true only after the fact Thus the following code fragment is incorrect because it goes around the w h i l e loop once too often:

for any value of a(x). The vacuum is thus invariant under U(I)em transformations, and the photon remains massless. Out of the four SU(2) X U(l}y generators T, Y, only the combination Q obeys relation (15.16). The other three break the symmetry and generate massive gauge bosons. To put it another way, due to the conservation of electric charge, we can only allow neutral scalars to acquire vacuum expectation values; hence, the choice of vacuum (15.15) for the charge assignments of (15.14). The same Higgs isospin doublet is essential for the generation of fermion masses (see Section 15.4). 15.3 Masses of the Gauge Bosons

int x; while( !cineof( 1 1

, p, the left-hand partial derivative with respect to bj is nonpositive and the right-hand partial derivative is nonnegative 66c The derivative of g(bO + td) with respect to t, according to the chain rule, is (J/Jt)g(bO + td) = (Vg(bO + td 'd At t = 0 it is (Vg(bO 'd To simplify notation, let h = Vg(bO) We want to choose d so that h'd < O Since h'h = Eh; > 0 (assuming h"* 0), we can choose d = -h Also,.

cin >> x; cout < < "Read " < < x < < endl;

Just as in Section 14.9, the gauge boson masses are identified by substituting the vacuum expectation value <1>0 for <I>(x) in the Lagrangian z. The relevant term in (15.13) is

returns t r u e if all is well Once an error has occurred, it should be cleared after recovery by a call to

However if the same read is attempted, it will fail again because the same characters remain in the input stream unread Typically a string or extra line will need to be read, and ignored, so that newly typed characters can be processed

cerr << 'Format error" << endl;

I( -ig~.W~ -

> 0 (because h'(X;Xc)-lh = f'f, where f = Xc(X;X)-Ih), and so we can choose d = -(X;X)-Ih = -(X;X)-I Vg(bO).

A manipulator, e n d l ' s function is to place a newline on the stream and then flush the stream buffer, forcing a write Other manjpulators, dec, h e x , and o c t , are used to change the output of integers to decimal, hexadecimal, and octal Thus

cout << 37 << oct < < 37 < < hex < < 37; / / still hexadecimal cout < < 37;

(15.17)

cout < < setiosflags( ios::showbase 1 ;

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