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Listing 8-13. Calling the First DescendantsAndSelf Prototype XDocument xDocument = new XDocument( new XElement("BookParticipants", new XElement("BookParticipant", new XAttribute("type", "Author"), new XComment("This is a new author."), new XElement("FirstName", "Joe"), new XElement("LastName", "Rattz")), new XElement("BookParticipant", new XAttribute("type", "Editor"), new XElement("FirstName", "Ewan"), new XElement("LastName", "Buckingham")))); IEnumerable<XElement> elements = xDocument.Element("BookParticipants").Elements("BookParticipant"); // First, I will display the source elements. foreach (XElement element in elements) { Console.WriteLine("Source element: {0} : value = {1}", element.Name, element.Value); } // Now, I will display each source element's descendant elements. foreach (XElement element in elements.DescendantsAndSelf()) { Console.WriteLine("Descendant element: {0}", element); } Now, you should see all the descendant elements and the source elements themselves. The results of this example are the following: Source element: BookParticipant : value = JoeRattz Source element: BookParticipant : value = EwanBuckingham Descendant element: <BookParticipant type="Author"> <!--This is a new author.--> <FirstName>Joe</FirstName> <LastName>Rattz</LastName> </BookParticipant> Descendant element: <FirstName>Joe</FirstName> Descendant element: <LastName>Rattz</LastName> Descendant element: <BookParticipant type="Editor"> <FirstName>Ewan</FirstName> <LastName>Buckingham</LastName> </BookParticipant> Descendant element: <FirstName>Ewan</FirstName> Descendant element: <LastName>Buckingham</LastName> So the output is the same as the first prototype for the Descendants operator, except it does include the source elements themselves, the BookParticipant elements. Don t let the existence of the comment in the results fool you. It is not there because the comment was returned by the DescendantsAndSelf operator; it is there because I display the BookParticipant element, which was returned by the operator. For the second DescendantsAndSelf prototype, I will use the same example as the first prototype, except specify a name the element must match to be returned, as shown in Listing 8-14.

Listing 8-14. Calling the Second DescendantsAndSelf Prototype XDocument xDocument = new XDocument( new XElement("BookParticipants", new XElement("BookParticipant", new XAttribute("type", "Author"), new XComment("This is a new author."), new XElement("FirstName", "Joe"), new XElement("LastName", "Rattz")), new XElement("BookParticipant", new XAttribute("type", "Editor"), new XElement("FirstName", "Ewan"), new XElement("LastName", "Buckingham")))); IEnumerable<XElement> elements = xDocument.Element("BookParticipants").Elements("BookParticipant"); // First, I will display the source elements. foreach (XElement element in elements) { Console.WriteLine("Source element: {0} : value = {1}", element.Name, element.Value); } // Now, I will display each source element's descendant elements. foreach (XElement element in elements.DescendantsAndSelf("LastName")) { Console.WriteLine("Descendant element: {0}", element); } The results of this example are the following: Source element: BookParticipant : value = JoeRattz Source element: BookParticipant : value = EwanBuckingham Descendant element: <LastName>Rattz</LastName> Descendant element: <LastName>Buckingham</LastName> The results only include the descendant elements that match the name I specified. There isn t much evidence that I called the DescendantsAndSelf operator, as opposed to the Descendants operator, since the source elements were not returned due to their name not matching the specified name. Again, as with all the operators that return elements from multiple levels of the XML tree that accept a name argument that the elements must match to be returned, it just doesn t seem likely that you will need the AndSelf versions of the operators, because you probably wouldn t have that many levels of elements having the same name.

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In VoiceXML, prompts are specified using the <prompt> element. Here is the first prompt in the sample application: <prompt>Welcome to XYZ Savings and Loan</prompt> This will use the TTS engine to render the prompt. This simple prompt will speak only the in-line text, Welcome to XYZ Savings and Loan. By using <prompt> element attributes, you can control various aspects of your prompts, as described in the following sections.

For this example, I am going to first display the count of the presidents array, next I will concatenate the presidents array with itself, display the count of the resulting concatenated sequence, then call the Distinct operator on that concatenated sequence, and finally display the count of the distinct sequence which should be the same as the initial presidents array. To determine the count of the two generated sequences, I will use the Count Standard Query Operator. Since it is a nondeferred operator, I will not cover it in this chapter. I will cover it in the next chapter, though. For now, just be aware that it returns the count of the sequence on which it is called. The code is in Listing 4-34. Listing 4-34. An Example of the Distinct Operator string[] presidents = { "Adams", "Arthur", "Buchanan", "Bush", "Carter", "Cleveland", "Clinton", "Coolidge", "Eisenhower", "Fillmore", "Ford", "Garfield", "Grant", "Harding", "Harrison", "Hayes", "Hoover", "Jackson", "Jefferson", "Johnson", "Kennedy", "Lincoln", "Madison", "McKinley", "Monroe", "Nixon", "Pierce", "Polk", "Reagan", "Roosevelt", "Taft", "Taylor", "Truman", "Tyler", "Van Buren", "Washington", "Wilson"}; // Display the count of the presidents array. Console.WriteLine("presidents count: " + presidents.Count()); // Concatenate presidents with itself. Now each element should // be in the sequence twice. IEnumerable<string> presidentsWithDupes = presidents.Concat(presidents); // Display the count of the concatenated sequence. Console.WriteLine("presidentsWithDupes count: " + presidentsWithDupes.Count()); // Eliminate the duplicates and display the count. IEnumerable<string> presidentsDistinct = presidentsWithDupes.Distinct(); Console.WriteLine("presidentsDistinct count: " + presidentsDistinct.Count());

public interface UnderwritingBusinessDelegate { public void underwriteNewPolicy(String productCd,String name,int age); }

If this works as I expect, the count of the elements in the presidentsDistinct sequence should equal the count of the elements in the presidents sequence. Will our results indicate success presidents count: 37 presidentsWithDupes count: 74 presidentsDistinct count: 37 Yes, they do!

This operator has one prototype I will cover. The Union Prototype public static IEnumerable<T> Union<T>( this IEnumerable<T> first, IEnumerable<T> second); This operator returns an object that, when enumerated, first enumerates the elements of the input sequence named first, yielding any element that is not equal to a previously yielded element, then enumerates the second input sequence, again yielding any element that is not equal to a previously yielded element. An element is determined to be equal to another element using their GetHashCode and Equals methods.

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